So to modify content in Sling, you have multiple options, the Sling default POST Servlet also called the SlingPostServlet is one of them. You can look at grizzly, glassfish, or jetty to use the NIO capabilities of Java.As always in life there is more than one way to do it. But we can also improve our network handling. } Controlling network I/O in your appserver This depends on your filesystem blocksize and your disk cache size and so on.īin.close() Option 4: Using a static byte array: to avoid reallocation, we create a final buffer and use synchronized to control access to it. You can experiment with different buffersize to see the effect. Option 1 : The naive way, we take the inputstream and write it byte per byte to an outputstream.įileOutputStream fout= new FileOutputStream (yourPathtowriteto) įout.close() Option 2: We use bufferstreams to do the jobįileOutputStream fout= new FileOutputStream ( yourPathtowriteto ) īufferedOutputStream bout= new BufferedOutputStream (fout) īufferedInputStream bin= new BufferedInputStream(stream) īin.close() Option 3: Use a byte array instead of per byte. describes different ways you can use to write your file to disk Now that we have the name, the stream we can write it to the correct place on this, without tempfiles and overloaded memory! } How to write is to disk most efficiently: ('File field ' + name + ' with file name ' + item.getName() + ' detected.') ('Form field ' + name + ' with value ' + Streams.asString(stream) + ' detected.') ServletFileUpload upload = new ServletFileUpload() įileItemIterator iter = upload.getItemIterator(request) Now we are ready to parse the request into its constituent items. Check that we have a file upload requestīoolean isMultipart = ServletFileUpload.isMultipartContent(request) InputStream uploadedStream = item.getInputStream() įileupload provides a way to avoid the write to disk before your servlet can handle. String contentType = item.getContentType() ĭefault implementation of FileUpload, write() will attempt to rename the file to the specified destination, but if you want you can read the stream directly. You access the file characteristics like this: List / FileItem / items = upload.parseRequest(request) ServletFileUpload upload = new ServletFileUpload(factory) Create a factory for disk-based file itemsĭiskFileItemFactory factory = new DiskFileItemFactory() įtSizeThreshold( yourMaxMemorySize) įtRepository( yourTempDirectory) the streaming version + combinations of writing FileIO using various buffers.you have a streaming api for processing the different multipart streams.you have direct access to the incoming stream without any temporary file.you can control the memory size within your servlet.It's the java fileupload component from the apache commons project. Having examined the rails alternatives for large file upload, we turned towards other alternatives and YES, did we find one!

Apache file upload example